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Calculus - Partial Fractions - Stewart Calculus Solution, 7th ET Edition

Offered By: blackpenredpen via YouTube

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Calculus Courses Integral Calculus Courses Rational Functions Courses Partial Fractions Courses

Course Description

Overview

Dive into a comprehensive tutorial on partial fractions in calculus, focusing on Section 7.4 of Stewart's Calculus 7th Edition. Learn various techniques including the cover-up method, handling repeated linear factors, and dealing with complex denominators. Master integration methods such as completing the square and substitution, while working through numerous examples like integrating x^4/(x-1) and (5x+1)/((2x+1)(x-1)). Explore the reasoning behind these methods and practice designing your own integrals. Perfect for students seeking to deepen their understanding of partial fraction decomposition and its applications in calculus.

Syllabus

[Calculus] Sect 7.4 #7, Integral of x^4/(x-1), Partial Fraction, Stewart Calc 7th ET ed.
Q63, FAST WAY TO DO PARTIAL FRACTION FOR INTEGRALS.
the cover-up method & why it works! (for partial fractions decomposition).
This is how we partial fraction, repeated linear factors, "build up the power".
This is how we partial fraction, repeated linear roots, "cover-up method".
build up power for partial fractions? (design your own integrals#2).
[Calculus] Sect 7.4 #9, Integral of (5x+1)/((2x+1)(x-1)), Partial Fraction, Stewart Calc 7th ET ed.
Why cover-up method for partial fraction works? sect 7.4 #9.
Sect 7.4 #19, Partial Fraction with repeated linear factor.
Sect 7.4 #19, Partial Fraction with Cover Up.
[Calculus] Sect 7.4 #19, Partial Fraction, Stewart Calc 7th ET ed.
[Calculus] Sect 7.4 #21, Integral of (x^3+4)/(x^2+4), Partial Fraction, Stewart Calc 7th ET ed.
integral of 1/(x^2+a^2).
Partial Fraction 10/((x-1)(x^2+9)).
[Calculus] Sect 7.4 #23, Integral of 10/((x-1)(x^2+9)), Partial Fraction, Stewart Calc 7th ET ed.
Integral of x/(x^2+9).
integration with completing the square, Sect 7.4 #29.
Q68, integral of 1/(x^3+x),.
partial fraction for 1/(x(x^2+1)).
Substitution first, then partial fractions, integral of 1/(sqrt(x)+cube root of x).
Q62, Integral by completing the square, and u sub, calculus 2.


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blackpenredpen

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